What values of a and b make the equation true? sqrt(648)=sqrt(2^a•3^b)

Ответ:

slowmotion

04.01.2022

ANSWER

The value of a and b are:

a=3,b=4

EXPLANATION

The expression given to us is

$\sqrt{648} = \sqrt{ {2}^{a} \times {3}^{b} }$

We square both sides of the equation to obtain

$648= {2}^{a} \times {3}^{b}$

We now find the prime factorization of 648 to obtain,

${2}^{3} \times {3}^{4} = {2}^{a} \times {3}^{b}$

We now compare the exponents on both sides of the equation to obtain,

a=3,b=4

Therefore the correct option is C

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Ответ:

salgado100400

12.03.2022

Mathematics

2/3

Step-by-step explanation

Since AB is a midsegment parallel to XY, its slope and the slope of XY are the same.

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What values of a and b make the equation true? sqrt(648)=sqrt(2^a•3^b)
a) a=3, b=2
b) a=2, b=3
c) a=3, b=4
d) a=4, b=3

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What values of a and b make the equation true? sqrt(648)=sqrt(2^a•3^b) a) a=3, b=2 b) a=2, b=3 c) a=3, b=4 d) a=4, b=3

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What values of a and b make the equation true? sqrt(648)=sqrt(2^a•3^b)
a) a=3, b=2
b) a=2, b=3
c) a=3, b=4
d) a=4, b=3