jairopanda8
24.07.2021 •
Mathematics
When A = 300, solve the equation
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Ответ:
Solution given:
a=300
and equation is:
x²-40x+a=0
when a=300
x²-40x+300=0
making it a perfect square
x²-2*20x+20²-20²+300=0
(x+20)²-400+300=0
(x+20)²=100
x+20=±10
taking positive
x+20=10
x=10-20
x=-10
taking negative
x+20=-10
x=-10-20
z=-30
when A=300
x=-10 or -30
Ответ:
5/3 + 5/6
10/6 + 5/6
she needs 15/6 or 2 3/6 or 2 1/2 cups of sugar