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dchirunga23
14.02.2020 •
Mathematics
When a particular mass-spring system is started by stretching the spring 3 cm, one complete oscillation takes 4 seconds.
(a) If instead the initial stretch had been 5 cm, how long would it take for one complete oscillation?
Time for one oscillation = s
(b) If the mass were doubled, what would the period of the system be?
Period = s
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Ответ:
A. 5.16 s.
B. 5.66 s.
Step-by-step explanation:
A.
For a simple harmonic motion,
T = 2pi (sqrt * (l/g))
Given:
L1 = 3 cm
T1 = 4 s
L2 = 5 cm
T2 = ?
4 = 2pi*sqrt(3/g)
g = 7.4
At, L2,
T2 = 2pi*sqrt(5/7.4)
= 5.16 s.
B.
M1 = M1
M2 = 2*M1
For a simple harmonic motion,
T = 2pi (sqrt * (m/k))
4 = 2pi (sqrt * (M1/k))
M1/k = 0.405
Inputting the above values,
T2 = 2pi (sqrt * (2*M1/k))
= 2pi (sqrt * (2 * 0.405))
= 5.66 s.
Ответ: