Mathematics: When i get to simplifying the d^-2 what do i do with it?

the distribution is left tailedA....

When i get to simplifying the d^-2 what do i do with

rachelvasky9

10.01.2022

$\bold{\frac{5d^5-4c^3d^{14}+6c}{c^2d^{10}}}$

Step-by-step explanation:

$\bold{\frac{75c^2d^{-2}-60c^5d^7+90c^3d^{-7}}{15c^4d^3}}$

$\bold{75c^2d^{-2}=\frac{75c^2}{d^2}}$

$\bold{90c^3d^{-7}=\frac{90c^3}{d^7}}$

$\bold{=\frac{\frac{75c^2}{d^2}-60c^5d^7+\frac{90c^3}{d^7}}{15c^4d^3}}$

Join $\bold{\:\frac{75c^2}{d^2}-60c^5d^7+\frac{90c^3}{d^7}:\quad \frac{75c^2d^5-60c^5d^{14}+90c^3}{d^7}}$

$\bold{=\frac{\frac{75c^2}{d^2}-60c^5d^7+\frac{90c^3}{d^7}}{15c^4d^3}}$

Apply Fraction Rule: $\bold{\frac{\frac{b}{c}}{a}=\frac{b}{c\:\cdot \:a}}$

$\bold{=\frac{75c^2d^5-60c^5d^{14}+90c^3}{d^7\cdot \:15c^4d^3}}$

Factor $\bold{75c^2d^5-60c^5d^{14}+90c^3:\quad 15c^2\left(5d^5-4c^3d^{14}+6c\right)}$

$\bold{=\frac{15c^2\left(5d^5-4c^3d^{14}+6c\right)}{d^7\cdot \:15c^4d^3}}$

Cancel $\bold{\frac{15c^2\left(5d^5-4c^3d^{14}+6c\right)}{d^7\cdot \:15c^4d^3}:\quad \frac{5d^5-4c^3d^{14}+6c}{c^2d^7d^3}}$

$\bold{=\frac{5d^5-4c^3d^{14}+6c}{c^2d^7d^3}}$

$\bold{c^2d^7d^3=c^2d^{10}}$

= $\bold{\frac{5d^5-4c^3d^{14}+6c}{c^2d^{10}}}$

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