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TheViperMlg23676

TheViperMlg23676

28.01.2020 •

Mathematics

When n is divided by 14, the remainder is 9. what is the remainder when n is divided by 7?

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Ответ:

ballin3294

16.01.2022

If $n\equiv9\mod14$ , then there is some integer

for which $n=k+\dfrac9{14}$ where

would be a multiple of 14, i.e. $k\equiv0\mod14$ .

Because

is a multiple of 14, it's also a multiple of 7, so $k\equiv0\mod7$ .

This then means that $n\equiv9\equiv2\mod7$ , so the remainder upon dividing by 7 is 2.

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Ответ:

pamdhuber4224

28.06.2022

12 cm

Step-by-step explanation:

I don't think u have to use the phytagores theorem b/c the hypotenuse is 9+3=12. but if u have to use this.

${?a}^{2} + {b}^{2} = {c}^{2}$

${9}^{2} + {b}^{2} = {9 + 3}^{2}$

$81 + {b}^{2} = 9(9 + 3) + 3(9 + 3)$

$81 + {b}^{2} = 81 + 54 + 9$

$81 + {b}^{2} = 144$

${b}^{2} = 144 - 81 = 63$

${b}^{2} = \sqrt{53} = b = 7.93$

so if u found b then u can find c by using the same formula.

${a}^{2} + {b}^{2} = {c}^{2}$

${9}^{2} + {7.93}^{2} = {c}^{2}$

$81 + 63 = {c}^{2}$

${c}^{2} = 81 + 63 = 144$

$\sqrt{c} = \sqrt{144}$

c = 12

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