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desireeandrada9
04.02.2020 •
Mathematics
When the definition of a function involves a fraction, the function is undefined at any value that would make the denominator of the function
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Ответ:
zero
Step-by-step explanation:
Given a rational function then the denominator cannot be zero as this would make the function undefined.
Ответ:
zero
Step-by-step explanation:
We have to fill the correct word in the blank space.
Suppose
Substitute x=0 then we get
The function is not defined at x=0
Because the denominator of the function at x=0 is zero which makes the function not define.
When the definition of a function involves a fraction , the function is undefined at any value that would make the denominator of the function zero.
Ответ:
The correct answer is: " 6 " .
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{ that is; the simplified expression given is: " 6" [positive 6].
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Step-by-step explanation:
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Given the expression; which is intended to be:
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Simplify: " 1 + √ [ - (-5²)( - 1³) ] " ?
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Note:
Refer to "comments below" typed directly under 'where the question itself is asked' —for clarification.
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First, solve and simplify the value under the square root sign:
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- (-5²) (-1 ³) = ?
→ (- 1)( - 5²) (- 1³) = ?
↔ (- 5²)(- 1)( - 1³ ) = ?
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- 5² = -5 * -5 = 25 ; {Note: A negative * a negative = a positive ).
→ Now, multiply this value by: "(-1)" ;
(-1) * (25) = -25 ;
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Now, (-25) * (-1³) = ?
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Let us simplify: " ( - 1 ³ ) " ;
" ( - 1³ ) = (-1 * -1 * -1) =
( -1 * -1) * -1 = ? ;
Note: " (-1 * -1) = 1 (positive one) ;
→ {since: " a negative * a negative = a positive " .}.
Then, 1 * (-1) = -1 (negative one);
→ {since: a "positive times a negative = a negative"} ;
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So: " ( - 1³) = - 1 " ;
So: (-25) * (-1³) = (-25) * (-1) = 25 (positive 25) ;
→ {since: a "negative times a negative = a positive" ; and since:
" any value, multiplied by "1" ; results in that same original value."}.
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So, back to our problem:
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Simplify: " 1 + √ [ - ( - 5² ) ( - 1 ³ ) " ?
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= 1 + √25 ; _______________________________________________
{Note that: "√25 = 5 " ; 25 is a "perfect square";
since: 5² = 5 * 5 = 25 ; and "25" is known as a "perfect square" ; since the square root of the non-zero positive integer [in this case: " 25 ") ; results in a non-zero positive integer [in this case: " 5 " .].
If not known by trial and error; or by common known knowledge, one may use a calculator to find: " √25 " ; to get: " 5 " .
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So: We can write our original expression:
" 1 +
" ;
= 1 + 5 ;
= 6 .
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The correct answer is: " 6 " {positive 6}.
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Hope this answer — and explanation — is helpful to you!
Wishing you the best in your academic endeavors
— and within the "" community!
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