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evryday2285
09.07.2020 •
Mathematics
When the polynomial P(x)=ax^3+bx^2+3x-10 is divided by x+1, the remainder is -8. P(x) has a factor of x+5. Find the values of a and b.
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Ответ:
a = 1, b = 6
Step-by-step explanation:
The equation given is as follows;
P(x) = a·x³ + b·x² + 3·x - 10
The above equation has a factor of x + 5, therefore, we have;
P(-5) = 0 = a·(-5)³ + b·(-5)² + 3·(-5) - 10
-125·a + 25·b + (-15) - 10 = 0
-125·a + 25·b - 25 = 0
-125·a + 25·b = 25(1)
Also, we are given that;
a·x³ + b·x² + 3·x - 10 divided by x + 1 as a remainder, R = -8, therefore;
P(-1) = -8 = a·(-1)³ + b·(-1)² + 3·(-1) - 10
-a + b - 13 = -8
-a + b = -8 + 13 = 5
-a + b = 5(2)
Multiply equation (2) by 25 and subtract from (1) gives
-125·a + 25·b - 25(-a + b) = 25 - 25×5
-100·a = 25 - 125 = -100
a = 1
Therefore, from equation (2) we have;
-1 + b = 5
b = 5 + 1 = 6.
Ответ:
Step-by-step explanation:
Unfortunately it's not clear what you mean by 6 Σ 2 3(0.5)^n-1. I am going to assume that you mean summing up from n = 2 to n = 6 of the expression 3(0.5)^(n-1). Note that the "n-1" must be enclosed in parentheses.
a(2) = 3(0.5)^(2 -1) = 3(0.5) = 1.5
a(3) = 3(0.5)^(3 -1) = 3(0.5)^2 = 0.75
a(4) = 3(0.5)^(4 -1) = 3(0.5)^3 = 0.375
a(5) = 0.1875
a(6) = 0.09375
Sum these up to find the final answer.
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