Where is the circumcenter of this triangle located? at a vertex of the triangle on a side of the triangle outside the triangle inside the triangle

We know that the diagonals of a rectangle bisect each other.

So, If we draw the second diagonal of the rectangle, it will bisect the first diagonal, which is the hypotenuse of the triangle.

Also, in a rectangle, the bisectors of the sides and the diagonals are concurrent.

Hence, if we draw bisectors of the two sides of the given triangle, these bisectors and the second diagonal, which is the bisector of the hypotenuse, meet at a point.

Circumcenter of a triangle is nothing but the point of intersection of the bisectors of the sides of the triangle.

Since the above bisectors and the hypotenuse (the first diagonal of the rectangle) are concurrent, the circumcentre lies on the hypotenuse.

Hence, the circumcenter lies on the hypotenuse of the triangle.

So you're given the function f(x)=. From here it's a simple plug in, since they're giving us our x-value, 2. (If this helps at all) a function is like a machine, you input something and it gives you an output. This these functions (f(x)) our input is an x-value, and we get a y-value. If you think of this and test a bunch of points on a graph then it'll make a whole lot of sense.

So with this problem, your input is 2, and our function (machine that'll give us our output) is . All you do is plug in 2 for all x's and solve:

= 14 

So 14 is your output, and your answer!
(lol sorry you got a whole lesson instead of just the answer :P)