Mathematics: Where is the vertex of the parabola? y = x2 + 6x + 7 above the x-axis on the x-axis on the y-axis below the x-axis

Where is the vertex of the parabola? y = x2 + - id261492076, morganamandro9437

Ответ:

DesperatforanA

15.03.2022

$\bf \textit{vertex of a vertical parabola, using coefficients}
\\\\
\begin{array}{llcccl}
y = & 1x^2& +6x& +7\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}
\qquad 
\left(-\cfrac{ b}{2 a}\quad ,\quad c-\cfrac{ b^2}{4 a}\right)
\\\\\\
\left( -\cfrac{6}{2(1)}~~,~~7-\cfrac{6^2}{4(1)} \right)\implies (-3~~,~~7-9)\implies (-3~~,~~-2)$

0,0(0 оценок)

Ответ:

chad65

23.05.2022

Mathematics

AX : XB as AB : AC

AX = 5

XB = 4

AC = 6

AB = x

Step-by-step explanation:

5 : 4 as to x : 6

ratios can also be written as fractions...

5/4 = x/6 ..now we have a proportion...so we cross multiply

(4)(x) = (5)(6)

4x = 30

x = 30/4

x = 15/2 < AB = 15/2

0,0(0 оценок)

Where is the vertex of the parabola? y = x2 + 6x + 7 above the x-axis on the x-axis on the y-axis below the x-axis

Ответ:

Ответ:

Ask your question to the AI advisor

More tips

Answers on questions: Mathematics

Ask an AI advisor a question