Which angles are in the same relative position on the same side of the transversal they are congruent and do not have the same vertex

I am going to build one table for each equation and so you can choose which one is representative of your tables.

x          y = (1/2)x + 24      y = (4/3)x - 36          y = 2x - 48          y = 6x + 12

-6         -6/2 + 24 = 21       4(-6)/3 - 36 = -44    2(-6)-48=-36        6(-6)+12=-24

0          0 + 24 = 24            0 - 36 = -36            0- 48 = -48          0 + 12 = 12

6          6/2 + 24 = 27        4(6)/3 - 36 = -28      2(6)-48=-36         6(6)+12=48

12       12/2+24=30           4(12)/3-36=-20       2(12)-48=-24       6(12)+12=84

So, you know how to build each table, just replace x with a number to obtain the corresponding value of y.