Which are the solutions of the quadratic equation?

Ответ:

iiomqjessica

15.03.2022

$x=\frac{7+\sqrt{65}}{2}, x=\frac{7-\sqrt{65}}{2}$

Step-by-step explanation:

We are given that a quadratic equation

x^2=7x+4

x^2-7x-4=0

We have to find the solutions of the quadratic equation.

a=1, b=-7,v=-4

Quadratic formula: $x=\frac{-b\pm\sqrt{b^2-4ac}{2a}$

Substitute the values in the quadratic formula

$x=\frac{-(-7)\pm\sqrt{(-7)^2-4(1)(-4)}}{2(1)}$

$x=\frac{7\pm\sqrt{49+16}}{2}$

$x=\frac{7\pm\sqrt{65}}{2}$

$x=\frac{7+\sqrt{65}}{2}, x=\frac{7-\sqrt{65}}{2}$

Hence, the solutions of quadratic equation are

$x=\frac{7+\sqrt{65}}{2}, x=\frac{7-\sqrt{65}}{2}$

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lyn36

24.02.2021

Oop)

Here's how!))

Dont talk about this is here! Good Luck!

-Aslina

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