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NatsuDDW
19.11.2019 •
Mathematics
Which equation describes this line?
(1.13)
(-2.4)
o a. y-1 = 3(x - 13)
o b. y= 2 = 3(x-4)
o c. y - 4 = 3 (x - 2)
o d . y - 4 = 3(x + 2)
Solved
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Ответ:
The equation of line with given points is y - 4 = 3 ( x + 2 ) .
Step-by-step explanation:
Given as :
The points of line are ( 1 , 13 ) and ( - 2 , 4 )
The point slope intercept equation of line is
y -
= m ( x -
)
Where m is the slope of line
So , Slope , m =![\frac{y_2 - y_1}{x_2 - x_1}](/tpl/images/0381/5247/0cb71.png)
Or, m =![\frac{4 - 13}{ - 2 - 1}](/tpl/images/0381/5247/ceea9.png)
Or, m =![\frac{ - 9}{ - 3}](/tpl/images/0381/5247/aa503.png)
∴ m = 3
Now The equation of line is
y -
= m ( x -
)
Or. y - 13 = 3 ( x - 1 )
Or, y - 13 = 3 x - 3
Or, y = 3 x - 3 + 13
∴ y = 3 x + 10
I.e y - 4 = 3 x + 6
Or, y - 4 = 3 ( x + 2 )
Hence The equation of line with given points is y - 4 = 3 ( x + 2 ) . Answer
Ответ:
how is this a question?