Mathematics: Which equation has no real roots? a. x2 – 6x + 12= 0 b. x2 – 25 = 0 c. x2 + 11x = 0 d. x2 + 12x + 11= 0

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Which equation has no real roots? a. x2 – 6x + 12=

Ответ:

abbygriffin8575

10.03.2022

Step-by-step explanation:

To find the number of real roots for a quadratic, we apply the discriminate. The discriminate is the inside portion of the square root from the quadratic formula.

yields 2 real roots b^2-4ac=0

yields 1 real root[tx]b^2-4ac<0[/tex] yields no real roots

a. x^2-6x+12=0 where a=1, b=-6, and c=12

b^2-4ac=(-6)^2-4(1)(12)=36-48=-12 has no real roots

b. x^2-25=0 where a=1, b=0, and c=-25

b^2-4ac=(0)^2-4(1)(-25)=0+100=1000) has 2 real roots

c. x^2+11x=0 where a=1, b=11, and c=0

b^2-4ac=(11)^2-4(1)(0)=121-0=-1210) has 2 real roots

d. x^2+12x+11=0 where a=1, b=12, and c=11

b^2-4ac=(12)^2-4(1)(11)=144-44=1000) has 2 real roots

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Which equation has no real roots? a. x2 – 6x + 12= 0 b. x2 – 25 = 0 c. x2 + 11x = 0 d. x2 + 12x + 11= 0

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