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PrinceBaphomet

PrinceBaphomet

17.10.2019 •

Mathematics

Which equation is y = (x + 3)2 + (x + 4)2 rewritten in vertex form?
y = 2(x + 7)2 – 73
y = (x + 7)2 – 24
y=2(x+(7/2))^2-(1/4)
y=2(x+(7/2))^2+(1/2)

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Ответ:

bvargas786p7aa8y

07.01.2022

y = (x + 3)2 + (x + 4)2= x²+9+6x+x²+16+8x=2x²+14x+25
y=2x²+14x+25
the vertex form of y=ax²+bx+c is y=a(x-h)²+k
where h= -b/2a
and k= c-b²/4a
so the vertex form is y=2(x-(-14/4))²+ 25-196/8=2(x+14/4)²+4/8=2(x+7/2)²+1/2
the answer is y=2(x+(7/2))^2+(1/2)

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Ответ:

Geo777

07.01.2022

The correct option is 4.

Step-by-step explanation:

The given equation is

y=(x + 3)^2+(x + 4)^2

Simplify the above equation.

y=x^2+6x+9+x^2+8x+16 $[\because (a+b)^2=a^2+2ab+b^2]$

y=2x^2+14x+25

y=2(x^2+7x)+25

Add and subtract the value of $(\frac{-b}{2a})^2$ in the above parenthesis.

$(\frac{-b}{2a})^2=(\frac{-7}{2(1)})^2=(\frac{7}{2})^2$

$y=2[x^2+7x+(\frac{7}{2})^2-(\frac{7}{2})^2]+25$

$y=2[x+(\frac{7}{2})]^2-2[(\frac{7}{2})^2]+25$ $[\because (a+b)^2=a^2+2ab+b^2]$

$y=2(x+\frac{7}{2})^2-\frac{49}{2}+25$

$y=2(x+\frac{7}{2})^2+\frac{50-49}{2}$

$y=2(x+\frac{7}{2})^2+\frac{1}{2}$

Therefore correct option is 4.

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Ответ:

joejoefofana

16.03.2023

C

Explanation:

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