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Nickanderson21
19.06.2020 •
Mathematics
Which equation represents a line parallel to the line whose equations is -2x + 3y = -4 and passes through the point (1,3)?
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Ответ:
2. y - 3 = 2/3 (x - 1).
Step-by-step explanation:
-2x + 3y = -4
3y = 2x - 4
y = 2/3 x - 4/3 - so the slope is 2/3.
The slope of a line parallel to it is also 2/3.
It also passes through the point (1, 3).
Using the point-slope form of a line:
y - y1 = m(x - x1) where m = the slope and (x1, y1) is a point on the line, we have:
y - 3 = 2/3 (x - 1) <--- is the required equation.
Ответ:
2
Step-by-step explanation:
parallel lines have same slope with different intercept
y= mx+b
m is going to be same with different b
so the given function is:
-2x+3y=-43y= 2x-4y= 2/3x - 4/3Given options:
1. y-3= - 2/3(x-1) ⇒ y= -2/3x +3 + 2/3 ⇒ y= -2/3x +11/3
it has different slope, so is not parallel2. y-3= 2/3(x-1) ⇒ y= 2/3x+3-2/3 ⇒ y= 2/3x + 7/3
it has same slope, so is parallelit should be passing through point (1,3)3= 2/3+7/3 ⇒ 3=3, yes it does3. y-3= -2/3(x+1) ⇒ y= - 2/3x +3- 2/3 ⇒ y= -2/3x + 7/3
it has different slope, is not parallel4. y-3= 2/3(x+1) ⇒ y= 2/3x +3+ 2/3 ⇒ y= 2/3x +11/3
it has same slope, so is parallelit should be passing through point (1,3)3= 2/3+11/3 ⇒ 3≠13/3, no it doesn'tОтвет:
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