Which equation shows that the pythagorean identity is true for Ø=pi? select the equation that is the form sin^2(pi)+cos^2(pi)=1 a.0^2 +1^2=1
b.0^2 +(-1)^2=1
c. 1^2+0^2=1
d.(-1)^2+0^2=1

B. 0² + (-1)² = 1

Step-by-step explanation:

Given the equation sin^2(pi)+cos^2(pi)=1

This can also be written as (sinπ)² + (cosπ)² = 1

According to trigonometry Identity;

sinπ = 0 and cosπ = -1

Substituting this values into the expression  (sinπ)² + (cosπ)² = 1 will give;

0² + (-1)² = 1

Hence the correct equation that shows that the pythagorean identity is

0² + (-1)² = 1. Option B is correct.

x=5/6

Step-by-step explanation:

-16x - 7 = 8x + 13

  -8          -8

-24x + -7 = 13   (Change addition to subtraction and add the opposite)

            7     7

-24x = 20

24        24

x = 0.8333333

x=5/6