Mathematics: Which expression is a sum of cubes? a. -64x^6y^12+125x^16y^3 b. -32x^6y^12+125x^16y^3 c. 32x^6y^12+125x^9y^3 d. 64x^6y^12+125x^9y^3

Which expression is a sum of cubes? a. -64x^6y^12+125x^16y^3

Ответ:

hihihi129473838

06.01.2022

Since $\sqrt[3]{32}\not\in\mathbb Z$ , you can omit B and C as possible solutions.

Now,

$-64x^6y^{12}+125x^{16}y^3=(-4x^2y^4)^3+(5x^{16/3}y)^3$

but since 16 is not divisible by 3, A is not correct either.

So D is the answer. To verify:

$64x^6y^{12}+125x^9y^3=(4x^2y^4)^3+(5x^3y)^3$

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Ответ:

netflixacc0107

16.11.2020

Mathematics

Clyde added -8+(-2), your supposed to multiply -8*(-2) the answer is j^16

Step-by-step explanation:

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Which expression is a sum of cubes?
a. -64x^6y^12+125x^16y^3
b. -32x^6y^12+125x^16y^3
c. 32x^6y^12+125x^9y^3
d. 64x^6y^12+125x^9y^3

Ответ:

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