![Zykuko](/avatars/3291.jpg)
Zykuko
20.11.2020 •
Mathematics
Which expression is equivalent to V-80?
O-4.5
O
-4./5;
4.5;
0
4.5
Solved
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Ответ:
Your answer is: 4v5i
Step-by-step explanation:
Hope this helped : )
Ответ:
Step-by-step explanation:
Given: Δ ABC, CM⊥ AB
Now, consider![AM:BM = 2:5 = 2x:5x](/tpl/images/0147/8245/75471.png)
Let In ΔCMA H=- 10 , P= 4 , B= 2x
By, Pythagoras theorem,![H^2=P^2+B^2](/tpl/images/0147/8245/2c3ea.png)
putting values we get,![10^2=4^2+(2x)^2](/tpl/images/0147/8245/9e555.png)
⇒![100=16+4x^2](/tpl/images/0147/8245/f62c1.png)
⇒![x^2= 21](/tpl/images/0147/8245/d694b.png)
⇒![x= \sqrt{21}](/tpl/images/0147/8245/237c0.png)
which gives us
and ![MB = 5x= 5\sqrt{21}](/tpl/images/0147/8245/72f72.png)
⇒![AB= 2\sqrt{21}+5\sqrt{21}](/tpl/images/0147/8245/0035f.png)
⇒![AB= 7\sqrt{21}](/tpl/images/0147/8245/06ae2.png)
Now, Let In ΔCMB H=- ? , P= 4 , B= 5√21
By, Pythagoras theorem,![H^2=P^2+B^2](/tpl/images/0147/8245/2c3ea.png)
putting values we get,![H^2=4^2+(5\sqrt{21})^2](/tpl/images/0147/8245/b2f62.png)
⇒![H^2=16+525](/tpl/images/0147/8245/c5605.png)
⇒![H^2=541](/tpl/images/0147/8245/d6567.png)
⇒![H= \sqrt{541}](/tpl/images/0147/8245/f0ced.png)
⇒![CB= \sqrt{541}](/tpl/images/0147/8245/22705.png)
Therefore,![AB = 7\sqrt{21}\\CB= \sqrt{541}](/tpl/images/0147/8245/343a3.png)