dale87
21.07.2019 •
Mathematics
Which function's graph has asymptotes located at the values x=pi/2+-npi? 1. y = sin x2. y = sec x3. y = cot x4. y = tan x a) 2 onlyb) 1 onlyc) 1 and 3 onlyd) 2 and 4 only
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Ответ:
Ответ:
Option 2 and 4
Step-by-step explanation:
Given : Function's graph has asymptotes located at the values
To find : Which function graph has asymptote given?
Solution :
An asymptote is a line or curve that approaches a given curve.
To find vertical asymptote the limit has to go to either ∞ or − ∞ , which happens when the denominator becomes zero.
The sine are defined for all real x, y is defined for all real x, so there are no vertical asymptotes.
So, Option 1 is not true.
In option 3,
When we put Denominator = 0
Value of x lie between
So, Option 3 is not true.
In Option 2,
When we put Denominator = 0
When cos x=0 the values of x is
Therefore, The graph of y= sec x has asymptote located at the values
So, Option 2 is correct.
In Option 4,
When we put Denominator = 0
When cos x=0 the values of x is
Therefore, The graph of y= tan x has asymptote located at the values
So, Option 4 is correct.
Therefore, Option 2 and 4 are correct.
Hence Option A is correct - 2 only
Ответ:
ASA congruence theorem: If two angles and the included side of one triangle are equal to the corresponding angles and side of another triangle, the triangles are congruent.
Step-by-step explanation:
I just did that one