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24.03.2021 •
Mathematics
Which is equivalent to the complex number i^32?
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Ответ:
where i^2 = -1 (minus one)
So, i^2 = -1
i^4 = (i^2)^2 = (-1)^2 = -1 X-1 = 1
like ;
i^32 = (i^2)^16 = (-1)^16 = -1 X -1 X-1 X -1 X-1 X -1 X-1 X -1 X-1 X -1 X-1 X -1 X-1 X -1 X-1 X -1 X
= 1
Step-by-step explanation:
Ответ: