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chasewilkinson123
31.07.2019 •
Mathematics
Which is the equation of a parabola with vertex (0, 0), that opens downward and has a focal width of 6?
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Ответ:
Opens downward:
(x-h)^2=4p(y-k)
Width focal: p=-6<0 (donwnward)
Replacing h=0, k=0 and p=-6 in the equation above:
(x-0)^2=4(-6)(y-0)
x^2=-24y
The equation of the parabola is x^2=-24y
Ответ:
x + y = 4
Step-by-step explanation:
Took the test and got it right.