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jeffljr2718
02.11.2019 •
Mathematics
Which of the following are vertical asymptotes of the function y = 3cot(1/2x) - 4?
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Ответ:
x=0 or ±2 nπ where n belongs to natural numbers.
Step-by-step explanation:
The " vertical asymptote " is a vertical line that the graph of a function approaches but never touches. To find the vertical asymptotes of a rational function we set denominator=0.
We are given function y=3 cot((1/2)x)-4
which could also be written as![y=3\times\frac{cos((1/2)x)}{sin((1/2)x)} -4\\\\y=\frac{3 cos((1/2)x)-4 sin((1/2)x)}{sin((1/2)x)}](/tpl/images/0356/9016/8f6ae.png)
for denominator to be equal to 0 we must have sin((1/2)x)=0
⇒ (1/2)x=0
⇒ x=0 or ±2 nπ where n belongs to natural numbers.
Hence, the vertical asymptotes of the given function is x=0 or ±2 nπ where n belongs to natural numbers.
Ответ:
Equation of the line: y=2
Step-by-step explanation:
So, the horizontal line will have the equation y=2 because the y-coordinate of the point is 2.