Which of the following is the equation of a circle with center (5, - 2) and a radius of 3? a.(x-5)^2+(y+2)^2=9 b.(x+5)^2+(y-2)^2=9 c.(x-5)^2+(y+2)^2=3 d.(x+5)^2+(y-2)^2=3

option a

Step-by-step explanation:

we know  the equation of a circle is:

(x-x1)^2 +(y-y2)^2= r^2

center= (x1,y2)

radius =r

in this case we have:

center= (5,-2)

r=3

so we have:

(x-5)^2 +(y-(-2))^2=9

finally we have:

(x-5)^2 +(y+2)^2=9

The relationship between <7 and <8 can be said to be vertically opposite angles. They are equal to one another and formed by the intersection of two straight lines. i.e. the intersection of lines C and D.

The special angles created by the intersection of lines C and D can be used to solve for y because they all are inter woven and connected to one another either supplemtarily or by being vertically opposite angles.

5y - 29 = 3y + 19( vertically opposite angles)

5y - 3y = 19 + 29

2y = 48

y = 48/2

= 24.

<7 = <8

<7 + 5y - 29 = 180°( angles on a straight line)

<7 = 180° + 29 - (5 × 24)

= 209 - 120

<7 = 89°

<8 = 89° (vertically opposite angles)