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taylorpayne525p8qxky
19.08.2019 •
Mathematics
Which of the following quadratic function has a maximum value of 16?
1- y=x^2+16
2- y=16-x^2
3- y=(x-16)^2
4- y=(x+16)^2
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Ответ:
When a quadratic is in the form
Let's take a look at all of these answers.
1) y = x² + 16
#1 in is general form. (y=ax²+bx+c)
a=1, b=0, c=16.
So we know that the min/max is 16. We don't know which it is, though.
2) y = -x² + 16
I've rearranged this equation to general form.
As you can see, this will have the same outcome as the previous, with the min/max being 16.
3) y = (x-16)²
This is in y = (x-h)² + k form, but there is no k, thus the min/max k = 0.
This is also true for 4) y = (x+16)².
Let's go back to #1 and #2.
While vertex form y = (x-h)² + k makes finding the vertex easy, it is a lot easier to know whether we have a minimum or a maximum in y = ax² + by + c form.
Simply put: If a is positive, the parabola opens upwards and we have a min.
If a is negative, it opens downwards and we have a max.
We want a maximum value of 16, so that means negative a.
Thus our answer is 2) y = -x² + 16
Ответ:
576.79
Step-by-step explanation:
To find the original selling price, use the current selling price and the second markdown to find the selling price after the first markdown. Then, use this selling price and the first markdown to find the original price.