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Serenitybella
27.01.2020 •
Mathematics
Which of the following sequences of transformations maps
figure 1 to figure 2?
90° clockwise rotation around
the origin, then a reflection
across the x-axis
90° counterclockwise rotation
around the origin, then a
reflection across the x-axis
-4
reflection across the y-axis, then
a reflection across the x-axis
reflection across the x-axis, then
a reflection across the y-axis
Solved
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Ответ:
Explanation:
The vertices of the figure 1 are:
(-3, 2)(-4, 5)(-3, 8)(-7,5)The vertices of figure 2 are:
(2, -3)(5, -4)(8, -3)(5, -7)By simple inspection, you can tell that if you rotate the figure 1 90º clockwise and then reflect the image across the x-axys you obtain the figure 2.
You can prove that analitically.
1. Rotation 90º clockwise
A 90º clockwise reotation is the same that a 270º counterclockwise rotation and the mathematical rule for this is:
(x,y) → (y, x)Applying that rule to the vertices of figure 1, you obtain:
(-3, 2) → (2, 3)(-4, 5) → (5, 4)(-3, 8) → (8, 3)(-7,5) → (5, 7)2. Reflection across the x-axis.
A reflection across the x-axis keeps the same x-coordinate and changes the sign of the y-coordinate. The rule is:
(x,y) → (x, -y)Applying that rule to the previous points yields to:
(2, 3) → (2, -3)(5, 4) → (5, -4)(8, 3) → (8, -3)(5, 7) → (5, -7)Which are the coordinates of the figure 2. Thus, you have proved that the sequence of transformations 90° clockwise rotation around the origin, then a reflection across the x-axis (first choice) maps the figure 1 to figure 2.
Ответ:
1. The given rectangular equation is
.
We substitute
.
Divide through by![\cos \theta](/tpl/images/1274/3047/ad5f3.png)
2. The given rectangular equation is:
This is the same as:
We use the relation![r^2=x^2+y^2](/tpl/images/1274/3047/4a0ab.png)
This implies that:
3. The given rectangular equation is:
This is the same as:
We use the relation
and ![y=r\sin \theta](/tpl/images/1274/3047/6eeb2.png)
This implies that:
Divide through by r
4. We have![x=\sqrt{3}y](/tpl/images/1274/3047/a5d17.png)
We substitute
and ![x=r\cos \theta](/tpl/images/1274/3047/87936.png)
This implies that;
5. We have![x=y](/tpl/images/1274/3047/095fc.png)
We substitute
and ![x=r\cos \theta](/tpl/images/1274/3047/87936.png)
This implies that;