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justbepunky
18.10.2020 •
Mathematics
Which of the tables represent a function?
PLEASE BE QUIIICCCKKK
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Ответ:
B
Step-by-step explanation:
A function can never have a 'x' with two values.
If you say f(x) = a, then there is only one number 'a' which satisfy. If however, you say f(x) = a & f(x) = b, then it's not a function, since there are two values of f(x).
Following this,
A: x = 3 has two f(x) = 2 & 1, so it's not a function
Similarly you can check for all.
There is only one table which x has a unique value.
Correct B
Note that, f(x) = a & f(x) = b, doesnt represent a function. If it is, then a = b is must.
Also, a function is possible only when it satisfies this. But
f(x) = a, f(y) = a, f(z) = a is possible.
Ответ:
m = - 2 is the value of m that the function y= e^mx is a solution of the differential equation, y' + 2y = 0.
Step-by-step explanation:
To determine all values of m so that the function y= e^mx is a solution of the given differential equation.
First, we will find y'.
From, y= e^mx
But,![y' = \frac{d}{dx}y](/tpl/images/0744/0394/6a5fd.png)
Hence,
∴![y' = me^{mx}](/tpl/images/0744/0394/4fd81.png)
Now, we will put the values of y' and y into the given differential equation y' + 2y =0
From the question,
and
Then,
becomes
Then,![me^{mx} = - 2(e^{mx}) \\\\](/tpl/images/0744/0394/01f05.png)
∴![m = -2](/tpl/images/0744/0394/66080.png)
Hence, m = - 2 is the value of m that the function y= e^mx is a solution of the differential equation, y' + 2y = 0.