![javibote](/avatars/22585.jpg)
javibote
10.12.2020 •
Mathematics
Which one of the following suggests that the data set is approximately normal?
a. A data set with 14, 68, and s41.
b. A data set with 1330, 2940, and s2440.
c. A data set with 2.2, 7.3, and s2.1.
d. A data set with 105, 270, and s33.
Solved
Show answers
More tips
- P Philosophy How to Develop Extrasensory Abilities?...
- O Other Everything You Need to Know About Kudyabliks...
- C Computers and Internet The Twitter Phenomenon: What it is and How to Use it...
- C Computers and Internet How to Choose a Laptop: Expert Guide and Tips...
- C Computers and Internet How to Choose a Monitor?...
- H Horoscopes, Magic, Divination Where Did Tarot Cards Come From?...
- S Style and Beauty How to Make Your Lips Fuller? Ideas and Tips for Beautiful Lips...
- C Computers and Internet How to Learn to Type Fast?...
- A Art and Culture Who Said The Less We Love a Woman, the More She Likes Us ?...
Answers on questions: Mathematics
- M Mathematics What is the surface area of a cone with a height of 15 and the diameter of 12?...
- B Business Match the terms to their definition. 1. annual percentage yield the amount of interest you will earn in one year from a savings account 2. interest thresholds different...
- M Mathematics 15 o 10 Which function is graphed? 5 -8 -6 14 -20 2 4 6 8 -5 O A. y = Sx2 +6, 3 1-x+6.53 B. y - ſx+6, 3 l-x+6,23 O C. Y- Sx2 +6.x 53 1-x+6, x 3 O D. y = . Sy? +6,23...
- M Mathematics Write each situation as a rate. John travels 150 miles in 3 hours. Cameron ate 5 apples in 2 days....
- H History HEEELLP PLEASE I REALLY NEED HELP A bar graph analyzing Deaths by Country. The x-axis is labeled Country with entries from left to right: Russia, British Empire, France,...
Ответ:
a. A data set with 14, 68, and s41.
Step-by-step explanation:
For a normally distributed data set; Q₁ and Q₃ will be 0.6745 × 2 = 1.349 standard deviation.
The interquartile range IQR = Q₃ - Q₁ = 1.349 ×![{\sigma}](/tpl/images/0969/4309/2b38f.png)
Q₁ Q₃
IQR = Q₃ - Q₁ 1.349 × ![{\sigma}](/tpl/images/0969/4309/2b38f.png)
a. 14 68 41 = 68 - 14 1.349 × 41
= 54 = 55.309
b. 1330 2940 2440 = 2940 - 1330 1.349 × 2440
= 1610 = 3291.56
c. 2.2 7.3 2.1 = 7.3 - 2.2 1.349 × 2.1
= 5.1 = 2.8329
d. 105 270 33 = 270 - 105 1.349 × 33
= 165 = 44.517
From the above calculation, we will see that option a have a data set that is approximately normal.
Ответ:
I took 20 and timsed it by 12