Which ordered pairs make both inequalities true? y<5x+2

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Ответ:

willijav000

18.07.2022

Mathematics

$4\sqrt{6}+16$

Step-by-step explanation:

Given the expression: $4\sqrt{6}+8\sqrt{4}$

$\sqrt{4}=2\\$Therefore, \\4\sqrt{6}+8\sqrt{4} =4\sqrt{6}+8*2\\ =16+4\sqrt{6}$

We can re-write the answer as:

$4\sqrt{6}+16$

The answer is irrational because the sum of a rational number and irrational number is an irrational number.

The correct option is B.

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