Which point lies on a circle with a radius of five units and center at p(6,1)

The equation of a circle is:

(x-h)^2+(y-k)^2=r^2

Where (h,k) is the center of the circle and r is the radius of the circle.  In this case we have (6,1) for the center and a radius of 5 so:

(x-6)^2+(y-1)^2=25

So any point that satisfies that equation lies on the circle.

-5

Step-by-step explanation:

The given system is

The corresponding coefficient matrix is shown in attachment.

The value of the system determinant, is the determinant of the coefficient matrix.

Which is