Which polynomial is factored completely? 121x^2+36y^2 (4x+4)(x+1) 2x(x^2-4) 3x^4-15n^3+12n^2

121x² + 36y²

Explanation:

The question is equivalent to, "which answer cannot be factored anymore?"

This is the sum of squares (11x)² +(6y)². Such a sum has no factorization in real numbers.The first factor can have a factor of 4 removed: (4x+4) = 4(x+1)The difference of squares can be factored: (x²-4) = (x-2)(x+2)Each term has a coefficient that is a multiple of 3, so 3 can be factored out.

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Step-by-step explanation:

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