Which rational expression does not have any excluded values?

a.x+2/2x2

b.2x+4/3x+3

c.6x-5/x2-7

d.x+2/-x2-5

d. (x+2)/(-x²-5)

Step-by-step explanation

 ƒ(x) = x + 2/(2x²)

The function is undefined when x =  0.

b. ƒ(x) = (2x + 4)/(3x + 3)

The function is undefined when 3x + 3 = 0, i.e., when x = -1.

c. ƒ(x) = (6x - 5)/(x² - 7)

The function is undefined when x² - 7 = 0, i.e., when x = √7.

d. ƒ(x) = (x+2)/(-x²-5) = -(x+2)/(x² + 5)

The function would be undefined if x² + 5 = 0, i.e., if x² = -5. However, the square of a real number cannot be negative.

This function has no excluded values.

Oh, really? Funny Joke!

Step-by-step explanation: