Which scenario best matches the linear relationship expressed in the equation y = 13.50x + 300? 1. Bobby has $300 in the yearbook fund and spends $13.50 on each yearbook. 2. Bobby has $13.50 in the yearbook fund and spends $300 on each yearbook. 3. Bobby has $300 in the yearbook fund and earns $13.50 for each yearbook sold. 4. Bobby has $13.50 in the yearbook fund and earns $300 for each yearbook sold.

Choice 3: Bobby has $300 in the yearbook fund and earns $13.50 for each yearbook sold.

Step-by-step explanation:

From the equation y = 13.50x + 300, we can derive that:

300 is the initial value, or y-intercept.

13.50 is the rate of change, or slope.

Let's go through each choice and eliminate:

1. Incorrect, because spending $13.50 on each yearbook would mean a negative slope.

2. Incorrect, because the initial value is $300, not $13.50.

3. Correct, because $300 is the initial value and earning $13.50 means a positive slope.

4. Incorrect, because the initial value should be $300.

Therefore, choice 3 is the correct scenario.

We're asked to find the number of solutions to this system of equations:

\begin{aligned} y&=-6x+8 3x+y&=-4 \end{aligned}

y

3x+y

​

=−6x+8

=−4

​

Let's put them in slope-intercept form:

\begin{aligned} y&=-6x+8 y&=-3x-4 \end{aligned}

y

y

​

=−6x+8

=−3x−4

​

Since the slopes are different, the lines must intersect. Here are the graphs

Step-by-step explanation: