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girlhooper4life11
16.06.2020 •
Mathematics
Which situation can be represented by this inequality? 50−3.50x>100−6x Select one: A. Daniel has a $50 Dunkin Donuts™ gift card and spends $3.50 a day. David has a $100 gift card and spends $6 a day. What is x, the number of days that need to pass for Daniel to have less money on his gift card than David? B. Daniel has a $50 Dunkin Donuts™ gift card and spends $6 a day. David has a $100 gift card and spends $3.50 a day. What is x, the number of days that need to pass for Daniel to have more money on his gift card than David? C.Daniel has a $50 Dunkin Donuts™ gift card and spends $3.50 a day. David has a $100 gift card and spends $6 a day. What is x, the number of days that need to pass for Daniel to have more money on his gift card than David? D. Daniel has a $50 Dunkin Donuts™ gift card and spends $3.50 a day. David has a $100 gift card and spends $6 a day. What is x, the number of days that need to pass for Daniel to have the same amount of money on his gift card as David?
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Ответ:
Option C is correct
Step-by-step explanation:
Given: inequality is![50-3.50x100-6x](/tpl/images/0687/3126/c688a.png)
To find: situation that can be represented by the given inequality
Solution:
Cost of Dunkin Donuts gift card with Daniel = $50
Amount spent by Daniel per day = $3.50
Cost of Dunkin Donuts gift card with David = $100
Amount spent by David per day = $6
Amount left with Daniel after x days =![\$(50-3.50x)](/tpl/images/0687/3126/4f8c0.png)
Amount left with David after x days =![\$(100-6x)](/tpl/images/0687/3126/21cc3.png)
According to question,
Amount left with Daniel after x days > Amount left with David after x days
So, he inequality that satisfies the situation is![50-3.50x100-6x](/tpl/images/0687/3126/c688a.png)
Option C is correct
Ответ:
80
Step-by-step explanation: