which statement is true about 41?
a. it is a prime number.
b. it is a composite number.
c. it is a whole number that is neither prime nor composite.
d. it is not a whole number.
! i'm not understanding

A

41 is not divisible by any number other than 1 and itself so it is prime and not composite and obviously 41 is a whole number so BCD are eliminated

You can re-write this quotient this way :

What's inside the square root must be greater than or equal to 0, because the domain of the square root function is defined on R+ (which is [0,+∞))

In other word we must find x so that :

at the end we get

28(x-1) ≥ 0

28x - 28 ≥ 0

28x ≥ 28

x ≥ 1

So the answer is B, x ≥ 1