Which statement is true of x2 + 8x - 6?
0 (x - 2) is a factor of the polynomial.
(x + 2) is a factor of pe polynomial.
(x – 4) is a factor of the polynomial.
The polynomial is prime.

Let f(x) be x^2+8x-6
x-2=0
x=2
f(2)=(2)^2+8(2)-6
= 4+16-6
= 20-6
= 14
(x-2) is not a factor of f(x).

x+2=0
x=-2
f(-2)=(-2)^2+8(-2)-6
= 4-16-6
= -18
(x+2) is not a factor of f(x).

x-4=0
x=4
f(4)= (4)^2+8(4)-6
= 16+32-6
= 10+32
= 42
(x-4) is not a factor of f(x).

Since none of the given factors are the factors of f(x), and the question states that one of the statements given above are true, the true statement is that the polynomial is prime.

69000

Step-by-step explanation: 1 kilo= 1,000 dec

69x1,000=69,000 it's basically like counting 1,000 decimeters 69 times