Which statements are true about y Less-than-or-equal-to 8 and its graph? Check all that apply.
y = 0 is part of the solution set.
y = 8 is part of the solution set.
y = 10 is part of the solution set.
There is an open circle on the graph at 8.
There is a closed circle on the graph at 8.
The arrow on the graph points left.
The arrow on the graph points right.

When the inequality sign is </> (less than/greater than), the dot is an open circle.

When the inequality sign is ≤/≥ (less than or equal to/greater than or equal to), the dot is a closed circle.

y = number that is a solution/makes the inequality true

y ≤ 8      (y is any number less than or equal to 8)

#1:    y = 0 is part of the solution set.

Yes because if you substitute/plug in 0 into "y" in the inequality, since y = 0:

0 ≤ 8         0 is less than 8.

#2:     y = 8 is part of the solution set.

Yes because if you plug it into the inequality:

8 ≤ 8       8 is equal to 8

#3:     y = 10 is part of the solution set.

No because if you plug it into the inequality:

10 ≤ 8         10 is not less than or equal to 8

#4:     There is an open circle on the graph at 8.

No because the inequality sign is ≤, so there should be a closed circle on 8.

#5:      There is a closed circle on the graph at 8.

Yes because the inequality sign is ≤

#6:    The arrow on the graph points left.

Yes because if the arrow is pointing left then the numbers are decreasing, and y is any number less than or equal to 8.

#7:     The arrow on the graph points right.

No because if the arrow is point right then the numbers are increasing, but y is not a number greater than 8.

Your answer is the 1st, 2nd, 5th, and 6th option

D.

Step-by-step explanation:

The co-ordinates of the triangle ABC are :

A(3,1)

B(2,6)

C(6,5)

The co-ordinates of the image triangle A'B'C' are :

A'(-5,4)

B'(-6,9)

C'(-2,8)

From the figure we can see that the triangle is translated left and up. The translation statement for such is given as:

where represents left shift by units and represents up shift by units.

Using point A to A'

Given value of

Solving for , we have:

Subtracting 1 from both sides.

∴

Thus the translation statement is given by: