Which system of equations does not have a real solution? Oy= x2 + 3x - 5 and x + y = -10
Oy= x2 + 3x - 5 and 4x + 5y = 20
Oy= x2+3x-5 and x + y = -9

Part a.

You need to solve the quadratic function h = -16t^2 + 60 t + 6 = 0

-16t^2 + 60 t + 6 = 0

Divide by 2, just to make the numbers easier

-8t^2 + 30t + 3 = 0

Use the quadratic formula to find the roots

t=[ -b ± √(b^2-4ac) ] /2a

t=[-30 ± √(30^2-4(-8)(3) ]/2(-8)

t=[-30 ± √(900 + 96) ]/(-16)

t=[-30 ± √(996) ]/(-16)

t=[-30 ± 31.56) ]/(-16)

t=[-61.56) ]/(-16) = 3.85 s

Part b)

h = -16t^2 + 60 t + 6
h (3) = -16(3)^2 + 60 (3) + 6 = -144 + 180 + 6 = 42 ft