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genyjoannerubiera
12.11.2019 •
Mathematics
Will give brainliest
an air force plane left nairobi and flew west at an average speed of 159 mph. a cargo plane left sometime later flying in the same direction at an average speed of 207 mph. after flying for 5.3 hours the cargo plane caught up with the air force plane. find the number of hours the air force plane flew before the cargo plane caught up.
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Ответ:
The air force plane travelled for a total of 6.9 hours.
SOLUTION:
Given, An Air Force plane left Nairobi and flew west at an average speed of 159 mph. A cargo plane left sometime later flying in the same direction at an average speed of 207 mph. After flying for 5.3 hours the cargo plane caught up with the Air Force plane.
We have to find the number of hours the Air Force plane flew before the cargo plane caught up.
Now, we know that,![\text { distance travelled }=\text { speed } \times \text { time }](/tpl/images/0370/1475/d79af.png)
For air force plane![\rightarrow \text { distance travelled }=159 \mathrm{x} \text { time taken by air force plane }](/tpl/images/0370/1475/18645.png)
Now, when cargo plane caught the air force plane the distance travelled by the planes will be equal.
So,![159 \times \text { time taken by air force plane }=207 \times 5.3](/tpl/images/0370/1475/a54c7.png)
Time taken by air force plane = 6.9 hrs
Ответ:
2 positive * 1 negative = negative
2 negative * 1 positive = positive
Step-by-step explanation:
one positive and 2 negative
(+ * -) * - =
positive times negative = negative * negative = positive
(+ * -) * - = +
now if we change the order by putting parenthesis
+ *( - * -)
negative time negative = positive
+ * (+) = positive
the result is positive
The result does not change because of where we put the parentheses.
- * + * + =
negative times positive = negative
negative * positive= negative
- * + * + = negative
The order does not matter