Will give brainliest answer to whoever answers ! first person to answer gets 100 ! the slope of pq is 5/2 .

which segments are perpendicular to pq ?

select each correct answer.

tu , where t is at (0, 2) and u is at (2, 7)

xy , where x is at (2, −5) and y is at (4, −10)

vw , where v is at (14, 5) and w is at (4, 9)

rs , where r is at (3, −4) and s is at (8, −6)

o RS¯¯¯¯¯ , where R is at (3, −4) and S is at (8, −6)

o VW¯¯¯¯¯¯ , where V is at (14, 5) and W is at (4, 9)

Step-by-step explanation:

Solve for each slope of the given line segments. For Line PQ, the slope if 5/2. To find the segment that is perpendicular to PQ, the slope must be -2/5.

Use the following equation:

slope (m) = (y₂ - y₁)/(x₂ - x₁)

Let: RS¯¯¯¯¯ , where R is at (3, −4) and S is at (8, −6)

(x₁ , y₁) = (3, -4) & (x₂ , y₂) = (8, -6)

Plug in the corresponding numbers to the corresponding variables:

m = (-6 - (-4))/(8 - 3)

m = (-6 + 4)/(8 - 3)

m = (-2)/(5)

m = -2/5

RS¯¯¯¯¯ , where R is at (3, −4) and S is at (8, −6) is an answer choice.

slope (m) = (y₂ - y₁)/(x₂ - x₁)

Let:

(x₁ , y₁) = (14, 5) & (x₂ , y₂) = (4, 9)

Plug in the corresponding numbers to the corresponding variables:

m = (9 - 5)/(4 - 14)

m = (4)/(-10)

m = -2/5

VW¯¯¯¯¯¯ , where V is at (14, 5) and W is at (4, 9) is an answer choice.

slope (m) = (y₂ - y₁)/(x₂ - x₁)

Let:

(x₁ , y₁) = (2 , -5) & (x₂ , y₂) = (4 , -10)

Plug in the corresponding numbers to the corresponding variables:

m = (-10 - (-5))/(4 - 2)

m = (-10 + 5)/(2)

m = -5/2

XY¯¯¯¯¯¯ , where X is at (2, −5) and Y is at (4, −10) is NOT an answer choice.

Let:

(x₁ , y₁) = (0 , 2) & (x₂ , y₂) = (2 , 7)

Plug in the corresponding numbers to the corresponding variables:

m = (7 - 2)/(2 - 0)

m = (5)/(2)

m = 5/2

TU¯¯¯¯¯ , where T is at (0, 2) and U is at (2, 7) is NOT an answer choice.

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my algebra calculator says that x=10.09

the .09 has a line over it btw!