Will give brainliest! I need help with those three questions! Please :)))

Okay so for the first question, if you simplify the equation, you get 5 = 6, which is never true. Therefore it has 0 solutions.
For the second question, if you simplify the equation you get 21 = 21, which is always true. Therefore it has infinite solutions.

Now let’s write the equation for the last question: 3p + 5 = 11, simplifying would give you 3p = 6, which means p = 2

Step-by-step explanation:

the 2nd line can be rewritten as y < x-3

So, any value that is less than both 4x+4 and x-3 will work

Pick any value you want for x, and figure y possibilities

x=0; x-3=-3, 4x+4=4, so y<-3 ... (0,-5) will work

I'm sure you can now come up with other pairs.