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110 large drinks, and 120 small drinks.

Step-by-step explanation:

Let's define the variables:

S =  number of small drinks he sold

L = number of large drinks he sold

We know that each small drink costs $1.00 and each large drink costs $1.50

Then the total revenue will be:

S*$1.00 + L*$1.50

We know that:

- He sold a total of 230 drinks, this is written as:

S + L  = 230

- The total revenue was $285, then:

S*$1.00 + L*$1.50 = $285

Then we have a system of equations:

S + L  = 230

S*$1.00 + L*$1.50 = $285

To solve this system we first need to isolate one variable in one of the equations, i will isolate S in the first equation:

S = 230 - L

Now we can replace this in the other equation to get:

(230 - L)*$1.00 + L*$1.50 = $285

Now we can solve this for L.

$230 - L*$1.00 + L*$1.50 = $285

$230 + L*$0.50 = $285

L*$0.50 = $285 - $230 = $55

L*$0.50 = $55

L = $55/$0.50 = 110

So 110 large drinks were sold.

Then with the equation

S + L = 230

We can find the value of S.

S = 230 - 110 = 120

S = 120

120 small drinks were sold.