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scm9170
10.12.2020 •
Mathematics
(with solution)
1.in the linear equation, m= 6 and b= -2, what is the equation in the slope intercept form
2.the line has a x-intercept of -2 and an y-intercept of 5. what is the equation of the line express in standard form
3.the line passes through the point (6,-13) and (-4,-3), what is the equation of the line express in standard form
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Ответ:
see explanation
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + b ( m is the slope and c the y- intercept )
(1)
Here m = 6 and b = - 2, then
y = 6x - 2
(2)
The equation of a line in standard form is
Ax + By = C ( A is a positive integer and B, C are integers )
Here m = - 2 and b = 5, then
y = - 2x + 5 ← equation in slope- intercept form
Add 2x to both sides
2x + y = 5 ← equation in standard form
(3)
Calculate the slope m using the slope formula
m =![\frac{y_{2}-y_{1} }{x_{2}-x_{1} }](/tpl/images/0969/2066/287b9.png)
with (x₁, y₁ ) = (6, - 13) and (x₂, y₂ ) = (- 4, - 3)
m =
=
= - 1 , then
y = - x + b ← is the partial equation
To find b substitute either of the 2 points into the partial equation
Using (- 4, - 3 ) , then
- 3 = 4 + b ⇒ b = - 3 - 4 = - 7
y = - x - 7 ← equation in slope- intercept form
Add x to both sides
x + y = - 7 ← equation in standard form
Ответ:
-0.01745240644 fo negative 1 and 0.01745240644 fo positive 1
Step-by-step explanation: