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brandistrothma
08.12.2019 •
Mathematics
With this simple trig problem- angle of two sectors of a circle
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Ответ:
K = (1/2)r^2(sin(θ) +θ)
Step-by-step explanation:
The area of the triangle to the left is ...
A1 = (1/2)r^2·sin(180°-θ) = (1/2)r^2·sin(θ)
The area of the sector to the right is ...
A2 = (1/2)r^2θ
so the total area of the blue shaded region is ...
K = A1 + A2 = (1/2)r^2·sin(θ) + (1/2)r^2·θ
K = (1/2)r^2(sin(θ) +θ)
Ответ: