Working together, 4 computers can complete a task in 11 minutes. if 2 of the original computes are replace with computers that each run 20% faster, how many minutes will it

First, let's make an equation out of the first sentence in the problem statement. When four of each computers are used, they can finish a task in 11 minutes together. The question is, how fast is the rate of each computer? We let that rate be x which is in units of hours per unit computer. So, the first equation would be:

4x = 11
Solving for x,
x = 2.75 minutes

That means that each of the four computers has an individual rate of 2.75 minutes. Now, for the succeeding sentence, we replace two of the computers with a much faster time. That means it would take a shorter time by 20%. The new time would then be:

New time = 2.75 ( 1 - 0.2) = 2.2 minutes

Therefore, the total amount of time for the task to be done by 2 original and 2 new computers is

Total time = 2(2.75) + 2(2.2)
Total time = 9.9 minutes

y = 4 + 2x

Step-by-step explanation:

Given,

The number of apples eaten by monkey everyday = 4,

Also, it eats two bananas for every banana that Tommy eats.,

I.e. if x represents the number of bananas Tommy eats,

The number of bananas eaten by monkey = 2x

So, the total number of fruits eaten by monkey = 4 + 2x

If y represents the total number of pieces of fruit the monkey eats,

⇒ y = 4 + 2x

Which is the required equation.