WORTH 100 POINTS! The function h(x) is quadratic and h(3) = h(-10) = 0. Which could represent h(x)?

1) h(x) = x2 - 13x - 30
2) h(x) = x2 - 7x - 30
3) h(x) = 2x2 + 26x - 60
4) h(x) = 2x2 + 14x - 60

Step-by-step explanation:

4. h(x) = 2x^2 + 14x - 60

Step-by-step explanation:

Given that h(x) is a quadratic.

Also, h(3) = h(-10) = 0

(A) h(x) = x^2 - 13x - 30

=> h(3) = 3^2 - 13(3) - 30

=> h(3) = 9 - 39 - 30

=> h(3) = -30 - 30

=> h(3) = -60

=> h(3) ≠ 0

(B) h(x) = x^2 - 7x - 30

=> h(3) = 3^2 - 7(3) - 30

=> h(3) = 9 - 21 - 30

=> h(3) = -12 - 30

=> h(3) = -42

=> h(3) ≠ 0

(C) h(x) = 2x^2 + 26x - 60

=> h(3) = 2(3^2) + 26(3) - 60

=> h(3) = 2(9) + 78 - 60

=> h(3) = 18 + 78 - 60

=> h(3) = 96 - 60

=> h(3) = 36

=> h(3) ≠ 0

(D) h(x) = 2x^2 + 14x - 60

=> h(3) = 2(3^2) + 14(3) - 60

=> h(3) = 2(9) + 42 - 60

=> h(3) = 18 + 42 - 60

=> h(3) = 60 - 60

=> h(3) = 0

And

=> h(-10) = 2(-10)^2 + 14(-10) - 60

=> h(-10) = 2(100) - 140 - 60

=> h(-10) = 200 - 200

=> h(-10) = 0

Clearly we have,

=> h(3) = h(-10) = 0

Hence, the correct option is (D) h(x) = 2x^2 + 14x - 60

6

Step-by-step explanation: