Mathematics: Would be very happy if you helped.Don’t spam guys

yes she has a enough string because 2.5 times 3 is 7.5...

Would be very happy if you helped.Don’t spam guys

Kiki18love

08.08.2021

$\\ \sf\longmapsto 41sin\Theta=40$

$\\ \sf\longmapsto sin\Theta=\dfrac{40}{41}$

Now

$\boxed{\sf cos\Theta=\sqrt{1-sin^2\Theta}}$

$\\ \sf\longmapsto cos\Theta=\sqrt{1-(\dfrac{40}{41})^2}$

$\\ \sf\longmapsto cos\Theta=\sqrt{1-\dfrac{1600}{1682}}$

$\\ \sf\longmapsto cos\Theta=\sqrt{\dfrac{1681-1600}{1681}}$

$\\ \sf\longmapsto cos\Theta=\sqrt{\dfrac{81}{1681}}$

$\\ \sf\longmapsto cos\Theta=\dfrac{9}{41}$

We know

$\boxed{\sf tan\Theta=\dfrac{Sin\theta}{Cos\Theta}}$

$\\ \sf\longmapsto \dfrac{tan\Theta}{1-tan^2\Theta}$

$\\ \sf\longmapsto \dfrac{\dfrac{sin\Theta}{cos\Theta}}{1-\dfrac{sin^2\Theta}{cos^2\Theta}}$

$\\ \sf\longmapsto \dfrac{\dfrac{\dfrac{40}{41}}{\dfrac{9}{41}}}{1-\dfrac{\dfrac{\left(\dfrac{40}{41}\right)^2}}{\left(\dfrac{9}{41}\right)^2}}}$

$\\ \sf\longmapsto \dfrac{\dfrac{\cancel{40}}{\cancel{9}}}{1-\dfrac{\cancel{40}^2}{\cancel{9}^2}}$

$\\ \sf\longmapsto \dfrac{9}{40}$

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