Write a quadratic equation that has integer coefficients

Ответ:

tenoi14

09.01.2022

The quadratic equation is: $x^2-11x+28=0\\$

Step-by-step explanation:

The quadratic equation with given solutions and can be written as:

(x-a)(x-b)=0

Given:

Solutions are 4 and 7.

The quadratic equation can be written as:

$(x-4)(x-7)=0\\$

We simplify it further to get it in standard form.

Using FOIL(Firsts Outsides Insides Lasts )

$(x\times x)+(x\times(-7))+((-4)\times x)+(-4\times(-7))=0\\\\x^2-7x-4x+28=0\\$

Combining like terms:

$x^2-11x+28=0\\$

The quadratic equation is: $x^2-11x+28=0\\$

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