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kaliyab191
21.11.2020 •
Mathematics
Write an equation in point-slope form, slope intercept form, and standard form for a line that passes through (-2,8) with slope 8/5 please help : don’t give answers if you aren’t sure
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Ответ:
9514 1404 393
y -8 = 8/5(x +2)y = 8/5x +56/58x -5y = -56Step-by-step explanation:
Since you're given a point and slope, it is convenient to start with that form.
Point-slope form
y -k = m(x -h) . . . . . line with slope m through point (h, k)
y -8 = 8/5(x +2) . . . point-slope equation
__
Slope-intercept form
y = mx + b . . . . . line with slope m and y-intercept b
The above equation can be rearranged to this form.
y = 8/5x +16/5 +8
y = 8/5x +56/5 . . . . . slope-intercept form
__
Standard form
ax +by = c
Multiplying by 5 and subtracting the y-term gives the general form equation ...
5y = 8x +56
8x -5y +56 = 0
8x -5y = -56 . . . . . . add -56 to put into standard form
Ответ:
Addition and Subtraction is Inverse Operations
Multiplication and Division is Inverse Operations