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eloqit3338
24.12.2020 •
Mathematics
Write an equation in slope-intercepts form for the line that passes through (5, -4) and is perpendicular to the line described by 2x-10y=0 EXPLAIN what you did in each step to arrive at your answer plz
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Ответ:
y = -5x + 21
Step-by-step explanation:
First, put 2x - 10y = 0 into slope intercept form to find the slope:
Subtract 2x from both sides:
-10y = -2x
Divide each side by -10:
-10y = -2x
y = 1/5x
So, the slope of the line is 1/5.
Perpendicular lines have opposite reciprocal slopes, so the slope of the other line will be -5.
Then, use the equation y = mx + b to plug in the slope and the point given.
Solve for b:
y = mx + b
-4 = -5(5) + b
-4 = -25 + b
21 = b
Lastly, plug in the slope and b into y = mx + b to create the equation in slope intercept form:
y = -5x + 21 is the equation
Ответ: