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evere11605
14.11.2020 •
Mathematics
Write an equation of the line given an intercepts. Express in standard form.
1. x – intercept is 4 and y – intercept is 3.
2. x – intercept is -2 and y – intercept is 5.
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Ответ:
Required equations in standard form are:
1. 3x+4y=12
2. -5x+2y = 10
Step-by-step explanation:
Standard form of equation is given as:
1. x – intercept is 4 and y – intercept is 3.
The points will be:
(4,0) and (0,3)
Slope: m =![\frac{y_2-y_1}{x_2-x_1}](/tpl/images/0898/3691/f6758.png)
Slope intercept form of line is:
Putting the values of m and b(y-intercept)
Multiplying whole equation by 4
2. x – intercept is -2 and y – intercept is 5
The points will be:
(-2,0) and (0,5)
Now
Putting the values of m and b in slope intercept form
Multiplying the equation by 2
Hence,
Required equations in standard form are:
1. 3x+4y=12
2. -5x+2y = 10
Ответ:
∠KNC = 99°
Step-by-step explanation:
∠JNM + ∠KNC = 180 (it is a straight line)
∠KNC = 180 - ∠JNM
∠KNC = 180 - 81
∠KNC = 99°